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MrMuchimi
3 years ago
12

Can someone please help me with the problems that aren't done please ASAP

Mathematics
2 answers:
Norma-Jean [14]3 years ago
4 0
Number 2. You first need to conver those two fractions to decimals to so 3/5 is 0.60 and 1/4 is 0.25 so this is the order: 1/4 , 0.4 , 0.55 ,3/5
Zanzabum3 years ago
3 0
I believe #8 would be 0.6, and #10 would be 65%.
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Which value is MEAN of the data set?
Fynjy0 [20]

Answer:

D

Step-by-step explanation:

There is no data set so there is no data to find the mean of.

3 0
3 years ago
what will come in the following series 20 25 23 28 26 31 29 34 _? answer is 31. please explain how?? urgent pls​
Assoli18 [71]

The series of numbers is adding 5 and then subtracting 2

20+5=25

25-2=23

23+5=28

28-2=26

and so on. Do you understand?

7 0
3 years ago
If 1/2 = 32/d what is d first answer gets brainerlist
Scilla [17]

Answer:

D would be equal to 64

You just need to multiply 32 by 2

4 0
3 years ago
Read 2 more answers
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
Find the value of x<br> Round your answer to the nearest tenth.<br><br> sin 33=7/x
DaniilM [7]
The value of x is 12.9
7 0
3 years ago
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