Answer:
Step-by-step explanation:
Given: In a parallelogram ABCD, diagonals intersect at O and ar(ABCD) is .
We need to find the area of triangle AOB.
We know that each diagonal divide the parallelogram in two equal parts and diagonals bisect each other.
It means both diagonals divide the parallelogram in 4 equal parts.
Hence, the values of ar(AOB) is .
Answer:
1.5
Step-by-step explanation:
The question is incomplete due to the probability distribution table, investigating you can find it so I will attach it.
Having the table, we need to find the mean of the probability distribution, which is defined as the sum of the product of probability and value of random distribution, that is:
M = Sum (xi) * P (xi)
We replace:
M = 0.5 * 0.07 + 1 * 0.2 + 1.5 * 0.46 + 2 * 0.2 + 2.5 * 0.07
M = 1.5
Therefore, the mean of the given table is 1.5
