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ANTONII [103]
3 years ago
13

A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l

oss of 20 percent of the dealer's purchase price for that car. If the dealer sold each car for $20,000, what was the dealer's total profit or loss, in dollars, for the two transactions combined?
Mathematics
1 answer:
amm18123 years ago
4 0

Answer:

total loss is $1000

Step-by-step explanation:

given data

profit = 20 %

loss = 20 %

selling  = $20000

To find out

dealer's total profit or loss

solution

first we find profit of 1 car i.e.

profit = selling - purchase price

purchase price of 25 % profit i.e. purchase price *1.25 = selling price

purchase price = 20000/1.25

purchase price = 16000

so profit = 20000 - 16000

profit = $4000

now we calculate loss price

loss =  purchase price - selling price

purchase price * 0.8 =  selling price

purchase price = 20000/0.8 = 25000

loss =  25000 - 20000

loss =  $5000

total purchased price = 16000 + 25000

total purchased price = $41000

total selling price = 20000 + 20000

total selling price = $40000

so total loss =  $41000 - $40000

total loss is $1000

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The correct answer is A. The number of dimes (d) and quarters (q) is 22, as said in the problem. So d + q = 22. We know that the total value of these dimes and quarters is $3.40 or 340 cents. We also know that dimes are worth 10 cents and quarters worth 25 cents. The total number of dimes and quarters would be represented like this: 10d + 25q = 340. Therefore A. is the correct answer.
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Determine whether the equation represents a direct variation. If it does, find the constant of variation. 7x = −6y
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The constant variation -7/6
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7 0
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You purchased an investment for $5000 that gains 11% in value every year.
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Answer:

After 20 years the investment will be worth 11,000$

Step-by-step explanation:

in order to solve the problem you have to turn the percent into a decimal by moving the percent sign twice to the left. which will result in ".11"

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Can someone help me on these 4 problems. I don't know how to do them
Harman [31]
Question 84:
The given triangle is an isosceles triangle.
We have measure angle 2 = measure angle 3
We are given that angle 1 = 70°
We know that the sum of the interior angles of the triangle is 180.
This means that:
180 = angle 1 + angle 2 + angle 3
180 = 70 + angle 2 + angle 3
angle 2 + angle 3 = 110
Since both angles are equal, therefore:
measure angle 2 = 110/2 = 55°
We are given that:
measure angle 2 = x + 64
This means that:
x + 64 = 55
x = 55 - 64
x = -9

Question 85:
The given triangle is an isosceles triangle.
We have the two base angles are equal.
Since one of them is 30°, this means that the other is also 30°
We know that the sum of the interior angles of the triangle is 180.
This means that:
180 = angle 1 + angle 2 + angle 3
180 = 30 + angle 2 + 30
angle 2 = 120
We are given that:
measure angle 2 = 14x - 6
This means that:
14x - 6 = 120
14x = 126
x = 126/14
x = 9

Question 86:
The given triangle is an isosceles triangle.
We have the two base angles are equal.
Since one of the base angles is 40°
This means that the other one is also 40°
Therefore:
measure angle 2 = 40°
We are given that:
measure angle 2 = 47 + x
This means that:
47 + x = 40
x = 40 - 47
x = -7

Question 87:
The given triangle is an equilateral triangle. This means that all three interior angles are equal and each is measuring 60°.
Therefore:
measure angle 2 = 60°
We are given that:
measure angle 2 = x + 71
This means that:
x + 71 = 60
x = 60 - 71
x = -11

Hope this helps :)
8 0
4 years ago
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