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Mazyrski [523]
3 years ago
9

7. The area of a square is 81 cm². Find the perimeter of the square. Answer?

Mathematics
2 answers:
Hatshy [7]3 years ago
7 0
The answer is 36 cms
beks73 [17]3 years ago
4 0

Answer:

324

Step-by-step explanation:

81x4= 324

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Which number is the opposite of the number 2? its -2 right?
Luba_88 [7]
Yes, you are correct, because -2 is 2 spaces away from the number line.
8 0
3 years ago
Lmk lmk i need answer asap
slamgirl [31]

Answer:

5+9=9+5

Step-by-step explanation:

Because ethier way it will be 14, but idl dont take my word yet...

5 0
3 years ago
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A circle has an area of 50 square meters. Which answer is closest to the measure of its diameter?
gregori [183]
Area of a circle is computed by multiplying pi to the square of the circle's radius.

A = πr²
50m² = 3.14 r²
50m²/3.14 = r²
r² = 15.92m²
r = √15.92m²
r = 3.99m

Diameter is computed by multiplying the radius twice.
d = 2r
d = 2(3.99m)
d = 7.98m or rounded up to 8 m
8 0
3 years ago
The original price of a skateboard was reduced by $15. The new price is $49.
olasank [31]

Answer:

The original price of a skateboard is $64

Step-by-step explanation:

Let

x ----> the original price of a skateboard

y ----> the new price of a skateboard

we know that

The linear equation that represent this problem is equal to

y=x-15 ----> equation A

y=49 ---> equation B

substitute equation B in equation A and solve for x

49=x-15

Adds 15 both sides

49+15=x

64=x

Rewrite

x=$64

6 0
3 years ago
What is the solution to log Subscript 5 Baseline (x + 30) = 3
GarryVolchara [31]

Answer:

The correct option is option (d).

Step-by-step explanation:

Logarithms are used basically to express large number.

Rules:

  • log_a(M.N)= log_aM+log_aN
  • log_a(\frac{M}{N})= log_aM-log_aN
  • log_a(M^k)=klog_aM
  • log_a(1)=0
  • log_a(a)=1
  • b^{log_{b}k}=k
  • log_ab=c \Leftrightarrow b=a^c

Here given that,

log_5(x+30)=0

Applying the last rule

\Rightarrow (x+30)= 5^3

\Rightarrow x+30 = 125

⇒x=125-30

⇒x=95

Therefore x=95.

5 0
3 years ago
Read 2 more answers
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