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pentagon [3]
3 years ago
10

a recipe called for 2 cups or liquid, which includes 1/4 cups molasses. What fraction of the liquid in the recipe is molasses?

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0
1 3/4 of the cup will be the other liquid because if you take 1/4 from 2, that would be 1 3/4.
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The ratio of Monarch butterflies to Queen butterflies at a butterfly farm was 5:2. If there are no additional butterflies at the
andrew-mc [135]
So we know if there are 5 groups/dozens of Monarch butterflies, there are 2 groups/dozens of Queen butterflies. In other words, there are 5 Monarch butterflies for every 2 Queen butterflies.

Then we can turn that into an equation.

5x = m \\ \\ 2x =q \\ \\ 5x + 2x = m + q
From the last equation we wrote we can see that the total number of butterflies in the farm is 7x.

When we compare the Queen butterflies to total butterflies, we get \frac{q}{m + q} = \frac{2x}{5x + 2x} = \frac{2x}{7x} = \frac{2}{7}

The ratio of Queen butterflies to total butterflies is 2:7.
7 0
3 years ago
The management of a relatively new social networking website named BooglePlus is conducting a pilot study comparing use of its o
zavuch27 [327]

Answer:

0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

Step-by-step explanation:

Given the data in the question;

sample size n = 28

slope of the least squares regression line of y on x or sample estimate = 0.0623

standard error = 0.0224

95% confidence interval

level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05

degree of freedom df = n - 2 = 28 - 2 = 26

∴ the equation will be;

⇒ sample estimate ± ( t-test) ( standard error )

⇒ sample estimate ± ( t_{\alpha /2, df) ( standard error )

⇒ sample estimate ± ( t_{0.05 /2, 26) ( standard error )

⇒ sample estimate ± ( t_{0.025, 26) ( standard error )

{ from t table; ( t_{0.025, 26) = 2.055529 = 2.056

so we substitute

⇒ 0.0623 ± ( 2.056 )( 0.0224 )

Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

5 0
3 years ago
Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.​
Helga [31]
<h3>Answer: Choice D. \angle SQR \cong \angle XQR</h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

7 0
3 years ago
When it was Tess' turn in the "Guess my number game, the gloves were off! She gave Davis the following 10 clues:
astra-53 [7]

The number is 999777888.

S<u>tep-by-step explanation:</u>

Reaching to the answer by solving the clues one by one.

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All the digits in each period are same. So a period of three adjacent digits will have same the same digit.for ex.777 is  a period

The number is greater than 7. So the digit in the millions place and higher is 9.

The number is divisible by 3. So the sum of all the digits should be divisible by 3.

The number is divisible by 4. So the number formed by last two digits of the number should be divisible by 4.

Thousands digit is 7.

The number that satisfies all the given conditions is 999777888.

5 0
3 years ago
How many seconds until the ball touches the ground
neonofarm [45]

Answer: 6.06 seconds

Step-by-step explanation:

This will not factor. The ball will hit the ground 6.06 seconds after thrown.

7 0
3 years ago
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