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lyudmila [28]
3 years ago
11

What is the solution of the system of equations? Enter the solution as an ordered pair (use decimal rounded to the nearest hundr

edth if necessary)
y=\frac{3}{2} x+\frac{5}{4} \\2x+4y=25
I may give Brainleist
Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer:

(2.5,5)

Step-by-step explanation:

y=3x/2 +5/4

4y=6x+5

-6x+4y=5

6x+12y=75

16y=80

y=5

x=5/2

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Answer:

4

Step-by-step explanation:

I just know

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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts
kirill115 [55]

Answer:

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666    

p_v =2*P(Z  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.5 represent the sample mean

\sigma=1.1 represent the population standard deviation

n=860 sample size  

\mu_o =4.6 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 4.6, the system of hypothesis would be:  

Null hypothesis:\mu = 4.6  

Alternative hypothesis:\mu \neq 4.6  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666  

P-value

Since is a two sided test the p value would be:  

p_v =2*P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

5 0
3 years ago
I'LL MARK BRAINLIEST PLEASE HELP
Fudgin [204]
<h3>Answer:</h3>

The number is 72

<h3 /><h3>Step-by-step solution:</h3>

Its hard to explain this really. Its kind of like a trial-and-error. Multiplying numbers by 8 with the second digit being 5 more than the units digit.

It takes time but eventually, youll find the answer.

Plus, You can search it up since theres already a pre-existing answer to this same question.

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2 years ago
You bike
Lyrx [107]
<h2>Answer:</h2>

<em>You will bike 30.2 miles in the seventh day according to the prediction.</em>

<h2>Explanation:</h2>

Here we have the following data, You bike

  • 5  miles the first day of your​ training,
  • 5.4 miles the second​ day,
  • 6.2 miles the third​ day, and
  • 7.8 miles the fourth day.

So we can know some facts:

  • From the first day to the second day the number of miles increases:

5.4-5=0.4mi

  • From the second day to the third day the number of miles increases:

6.2-5.4=0.8mi

  • From the third day to the fourth day the number of miles increases:

7.8-6.2=1.6mi

By taking a look at the pattern, we can see that each day you increases the number of miles by a factor of 2 compared to the previous day. So:

  • From the fourth day to the fifth day the number of miles increases:

x_{5}-7.8=3.2mi \\ \\ x_{5}=7.8+3.2=11mi, \ \text{Day 5}

  • From the fifth day to the sixth day the number of miles increases:

x_{6}-11=6.4mi \\ \\ x_{6}=6.4+11=17.4mi, \ \text{Day 6}

Finally:

  • From the sixth day to the seventh day the number of miles increases:

x_{7}-17.4=12.8mi \\ \\ x_{7}=12.8+17.4=30.2mi, \ \text{Day 7}

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How many zeros are significant figures in a measured mass of 0.010010 g?
tekilochka [14]
Answer: 3

The first two zeros are not sig figs, but the next three zeros are sig figs
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