The answer to your problem is -8/-3
$476 divide by 85% multiply by 100% to get the answer
Answer:
![6\dfrac{2}{3}](https://tex.z-dn.net/?f=6%5Cdfrac%7B2%7D%7B3%7D)
Step-by-step explanation:
![\dfrac{5}{\dfrac{3}{4}} = \dfrac{5}{1}\times\dfrac{4}{3}=\dfrac{20}{3}=6\dfrac{2}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B%5Cdfrac%7B3%7D%7B4%7D%7D%20%3D%20%5Cdfrac%7B5%7D%7B1%7D%5Ctimes%5Cdfrac%7B4%7D%7B3%7D%3D%5Cdfrac%7B20%7D%7B3%7D%3D6%5Cdfrac%7B2%7D%7B3%7D)
When dividing fractions, you just need to remember that all you need to do is get the inverse of the divisor and multipy.
So for the problem
5 = divident
3/4 = divisor
So we get the inverse of 3/4 which is 4/3 and then multiply.
Look above to see the process.
Answer:
The forklift truck can raise maximum of 43 boxes.
Step-by-step explanation:
We are given the following in the question:
Maximum limit of forklift truck =
1750 kilograms
Let x be the number of 40 kilogram boxes that this forklift truck can raise.
Thus, we can write the following inequality that describes the maximum number of boxes raised.
![40x \leq 1750\\\\x \leq \dfrac{1750}{40}\\\\x \leq 43.75\\Max(x) = 43](https://tex.z-dn.net/?f=40x%20%5Cleq%201750%5C%5C%5C%5Cx%20%5Cleq%20%5Cdfrac%7B1750%7D%7B40%7D%5C%5C%5C%5Cx%20%5Cleq%2043.75%5C%5CMax%28x%29%20%3D%2043)
Thus, the forklift truck can raise maximum of 43 boxes.
The answer is 192sq.cm.
REASONING: This would be by multiply the length by the height in order to get the area. 12*19 is equal to 192.
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