[6*2 (22+4) - 2*2(19+3)]0
=[12(26)-4(22)]0
=[312-88]0
=[27456]0
=0
Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D
Therefore also ∡2 = ∡3 (they are half of the congruent angles)
For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.
Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)
T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4
∡AOD = ∡BCD because their measure is the difference of congruent angles.
Answer:
-4
Step-by-step explanation:
The average rate of change of the interval [a,b] is (f(b)−f(a)) / (b−a)
Replacing a=−5, b=4, f(x)=−x^2−5x+12.
(f(b)−f(a))/(b−a) =12−5x4− 4^2 − (12−5 x(−5)−(−5)^2)/ (4−(−5))= −4.
Answer:
choice A
Step-by-step explanation:
Answer:
6x-4y=24
Step-by-step explanation:
From the graph, there are two intersections to be found one at (4,0) and another at (0,-6)
Now,
slope,m= y1-y2/x1-x2
=0+6/4-0
=3/2
The equation of the straight line passingt through the point (4,0) is
y-y1=m(x-x1)
or, y-0=3/2 (x-4)
or, 2y=3x-12
or, 3x-2y=12
or, 2(3x-2y)=2(12) [Multiplying both sides by 2]
or, 6x-4y=24
