Given that Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, the probability that each of their offspring will develop the disease is approximately 0.25.

Let X be the no of children having this disease out of 4 occasions

Then X has two outcomes and each trial is independent of the other trial

Hence X is binomial with n =4, and p = 0.25

a) $P(X=4) = 4C4 (0.25)^4 = 0.003906$

b) $P(X=1) = 4C1 (0.25)(0.75)^3\\= 0.4219$

c) $P(4th child/3 children did not) = 0.25$ since independent.

4 0

3 years ago

Stacy saved 30% on a single item. If she saved $60.00, what was the cost of the item before the discount?

kifflom [539]

$x-\ cost\ of\ item\\\\
30\%*x=60.00\\\\
0,3x=60.00\ \ \ |Divide\ by\ 0,3\\\\
x=200.00\\\\
Cost\ of\ item\ was\ equal\ to\ 200.00\$.
$

7 0

3 years ago

What is m X to the nearest degree?<br> Help plssss

aalyn [17]

Answer:

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos X = $\frac{adjacent}{hypotenuse}$ = $\frac{XY}{XZ}$ = $\frac{13}{18}$ , then

∠ X = $cos^{-1}$ ( $\frac{13}{18}$ ) ≈ 44° ( to the nearest degree ) → A

5 0

3 years ago

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