Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
18-7n+1= -9
You just have to ignore the first thing it asks for, and then write out what it's saying. Since it's asking for the difference, you have to subtract what it tells you to. In this case they are asking for you to subtract 7 times a number from 18 which is the same as writing 18-7n. Then, go back to the first thing it asks for and that wants you to add one. You now have this: 18-7n+1. Now all you have to do is set it equal to whatever it asks you for, which is -9. The final product should look like this:
18-7n+1= -9
I hope this helps and if you could let me know if I helped, that would be greatly appreciated!
So theres 366 days in a leap year,
you need to find hours, minutes, and then seconds
366 x 24 = 8,784 hours
8,784 x 60 = 527,040 minutes
527,040 x 60 = 31,622,400 seconds
31,622,400 seconds x 186,182 mps = 5.88 x 10^10
therefore light travels 5.88 x 10^10 in one leap year
Each increases by a certain amount called the common difference
4.4-2.8=1.6
6-4.4=1.6
7.7-6=1.7
hmm, some error
maybe you meant 7.6
common difference is 1.6
answer is C
56% = 14 questions
1% = 14 ÷ 56 = 0.25 questions
100% = 0.25 x 100 = 25 questions
Answer: 25 questions.
