Question

Find the solution set. The solution set for 7q^2 − 28 = 0 is { }. (Separate the solutions with a comma)

Answer 1

Hi there! The answer is {-2, 2}
Let's solve this problem step by step!

$7 {q}^{2} - 28 = 0$
First add 28 to both sides.

$7 {q}^{2} = 28$
Now divide both sides by 7.

${q}^{2} = 4$
Take the root of both sides, and the negative root of 4.

$q = \sqrt{4} \: \: or \: \: q = - \sqrt{4} \\ q = 2 \: \: \: \: \: \: or \: \: q = - 2$
Therefore the solution set to this equation is {-2, 2}

~ Hope this helps you!