Bob starts running. Bill starts running 5 seconds later. Write an expression to represent the varying number of seconds Bob has
been running in terms of t, the varying number of seconds Bill has been running. (Illustrate this situation with a diagram first)
1 answer:
Answer:
Y=t+5
Step-by-step explanation:
Bob starts running...(1)
Bill starts running 5 seconds later...(2)
From (1) and (2) we know that Bob had been running for 5 seconds when Bill started running.
The expression we are looking for is
Y=t+5
Y is the number of seconds Bob has been running
t is the number of seconds Bill has been running
Check the image for the diagram.
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Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±* √[(^ρ(1-^ρ))/n]
=
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!