Answer: the answers are below
Step-by-step explanation:
1 meal = 2/3 of a can of wet dog food, 1/8 of a bag of dry dog food, and 3/5 a patty of special meat
Food for 1 day: 2 meals = 2(2/3) = 4/3 of a can of wet dog food, 2(1/8) = 1/4 of a bag of dry dog food, and 2(3/5) = 6/5 a patty of special meat
The trainer goes to the store and buys 24 cans of wet food, 4 bags of dry food and 3 packages of meat (3*6 = 18 patties)
He has:
there is wet food for: 24/(4/3) = 24*3/4 = 18 days
there is dry food for: 4/(1/4) = 4*4 = 16 days
there is special meat food for: 18/(6/5) = 18*5/6 = 15 days
since the minimum for 15, 16 and 18 is 15 the dog will have food for 15 days and first he will run out of special meat.
Answer:
let the of bag of vendors be X
3donate X bag to give 996
3×x=996
3x=996
divide both side by 3
3x\3=996\3
x=332
each vendor donated 332bags of popcorn
L x w = 150+175t
=> l = (150+175t)/25
l = [25(6+7t)/25]
l = 6+7t
The expression of the length is l=6+7t
The y-intercept is 2. The y-intercept occurs when x is 0. In the graph, y is 2 when x is 0.
