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Mama L [17]
3 years ago
9

Which line has the steeper slope?

Mathematics
2 answers:
shutvik [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Edgen2020 the the answer is: B

Dmitrij [34]3 years ago
3 0
The line that has the steeper slope is line b
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Can someone help me with this math homework please!
jolli1 [7]

Answer:

(-3,-6) and (-3,2)

Step-by-step explanation:

A line with an undefined slope is vertical. In this case it must have x coordinates equal to -3

4 0
3 years ago
Eli had $10, but he lost some of it. His mom doubled the money he had left. Eli wrote the expression 2(10 – k) to show how much
Juli2301 [7.4K]

Answer:

Equation 1

In the story it said Eli's mom doubled the money he left, that is what the two represents. 10 is the original amount he had. -k is the money he lost.

Equation 2

20 is the the result of the original 10 being multiplied. -2k, now the 2 is still the amount that the mom doubled his amount by, and the k is how much money Eli lost.

Hope this helps!!


8 0
3 years ago
Read 2 more answers
Name the ray rhat angle PQR and angle SQR share
lyudmila [28]
<span>Ray Q is the ray that angle PQR and SQR shares. Because both angles has the ray of Q.
ray refers to a line with one endpoint
P is a ray, Q is a ray, R is a ray and S is a ray. When you put them together, they form angle.

Pls. see attachment for the presentation of the angle PQR and SQR and how they share ray Q</span>



7 0
3 years ago
Please help me, I am not sure of the answer.
coldgirl [10]
I think it’s b not sure tho
6 0
2 years ago
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{first sol'n}&11&x&11x\\&#10;\textit{second sol'n}&4&0.55&2.20\\&#10;------&-----&-------&-------\\&#10;mixture&y&0.77&0.77y&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;11+4=y\implies 15=\boxed{y}\\&#10;11x+2.2=0.77y\\&#10;----------\\&#10;11x+2.2=0.77\cdot \boxed{15}&#10;\end{cases}

solve for "x"
6 0
3 years ago
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