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Alex787 [66]
3 years ago
14

Answer all please.....^

Mathematics
1 answer:
postnew [5]3 years ago
8 0
#4) 1/6
#5) 1/2
#6) 4/15
#7) 8/15
#8) 11/15
#9) 12
#10) 15
#11) 112

Explanation
#4) There is one section marked 5 out of 6 sections.

#5) There are three odd-numbered sections out of 6 sections.

#6) 2 blue were tossed 4 times out of 15 tosses.

#7) 1 blue and 1 pink were tossed 8 ties out of 15 tosses.

#8) All blue was tossed 4 times out of 15; this means that all blue was not tossed 15-4=11 times out of 15.

#9) There are 4 choices for location and 3 choices for transportation; 4(3) = 12.

#10) There are 3 choices for level and 5 choices for character; 3(5) = 15.

#11) Since 30% are rock, 100%-30% = 70% are not rock.  70% = 70/100 = 0.7; 0.7*160 = 112.
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Answer:

a

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4*1/7

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-4(8-(-3))+7

Remove the parentheses, negative with negative will equal a positive so the new equation will be -4(8+3)+7. So 8+3=11, -4(11)+7. -4(11)=-44 and then add -44+7 which will equal -37
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Which statements are true about quadrilaterals? Choose all answers that are correct. A. All 4-sided shapes are parallelograms. B
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Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

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∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

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