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algol [13]
3 years ago
10

Whitch is greater -8 or +8

Mathematics
2 answers:
finlep [7]3 years ago
8 0
+8 is the greatest then -8
Llana [10]3 years ago
4 0
+8, it goes: -8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8. Hope this helps! :)
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Rewrite without absolute value sign for different values of x: y=− 2x+5 + 2x−5 if x<−2.5; if x>2.5; if −2.5≤x≤2.5
valentina_108 [34]

Answer:

x<-2.5 =(2x+5)-(2x-5) 2. 5-5

3.0

Step-by-step explanation:

PLz make brainlestiset answer

4 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
Simplify the following expression 8x+9-6x-7
mamaluj [8]
8x + -6x = 2x 2 + 2x
4 0
3 years ago
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The length of a rectangular plot is expressed as x²m and the breadth is xm if the area of the rectangular plot is 5832 sq cm the
Zanzabum

Answer:

442

Step-by-step explanation:

4 0
3 years ago
How many timnes does 43 go into 93
Charra [1.4K]

43 can fit into 93 two whole times.

After that, there's only room for another 7 inside the 93,
so there's no way to stuff the whole 43 in there again.

8 0
3 years ago
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