Question

In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3}

Answer 1

Answer:

v = 0.625 m/s

Step-by-step explanation:

Given that,

Total distance is 750 m

Logan swan 750 m in 1/3 hours

His swimming partner, Mila, swam 2/3 of Logan's distance in 1/4 hours.

Note: We need to find Logan's average swimming speed.

Average speed = total distance/total time taken

$v=\dfrac{750\ m}{\dfrac{1}{3}\times 3600\ s}\\\\v=0.625\ m/s$

So, Logan's average speed is 0.625 m/s.