All categories

4 years ago

a blouse is regularly sold for 28.50$ and is on a sale for one third off, what is the sale price of the dress

Mathematics

1 answer:

Olegator [25]4 years ago

3 0

1/3 of 28,50= 9,50 subtract this from 28.50 $19.00 is the sale price hope this helps

You might be interested in

Which statement about y = x2 + 7x - 30 is true?

Lady_Fox [76]

Answer:

D. The zeros are 3 and -10, because y = (x - 3)(x + 10).

Step-by-step explanation:

$y=x^2+7x-30$

$0=x^2+7x-30$

$0=(x+10)(x-3)$

Therefore, D is correct by the Zero Product Property

4 0

3 years ago

Given that y varies inversely as x, and y = 8 when x = 3, what is the value of y when x = 12?

NeTakaya

Answer:

y = 2 when x =12

Step-by-step explanation:

y = k/x ..............as y varies inversely as x

8 = k/3

k = 8 * 3

k = 24

So,

y = k/x

y = 24/12

y = 2

3 0

2 years ago

Read 2 more answers

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

6 0

3 years ago

Help plsss . 10 points !

Irina18 [472]

Your answer should be C :-)

6 0

3 years ago

Read 2 more answers

Find the product. (n³) . (n⁵)⁴

Alenkasestr [34]

Answer:

n^23

Step-by-step explanation:

n^3 · n^20 = n^23

6 0

3 years ago