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muminat
3 years ago
15

Find the mead, median, and mode

Mathematics
2 answers:
Ann [662]3 years ago
7 0

Answer:

Median 4 Mean 5.5 Mode 2

Step-by-step explanation:

grin007 [14]3 years ago
7 0

Answer:

<em>B. Mean: 5.5 Median: 4 Mode: 2</em>

Step-by-step explanation:

1, 1, 2, 2, 2, 4, 5, 5, 9, 15, 15

Mode: 2

Median: 4

Mean: 1 + 1 + 2 + 2 + 2 + 4 + 5 + 5 + 9 + 15 + 15 = 61/11 = 5.5

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Write and solve an equation to find the value of X
Mumz [18]
Angles on a straight line add up to 180 degrees so

45 + 3x = 180
Subtract 45 from both sides to remove the 45 on the left

3x = 135
Then divide both sides by 3
x = 45

Answer is X = 45
8 0
3 years ago
Read 2 more answers
Find the value of x and y <br>&lt;1=(10x) <br>&lt;2=(10y+20)<br>&lt;3 =100 ​
Rufina [12.5K]

Answer:

  1. 100
  2. 80
  3. 100
  4. 80

x = 10

y = 6

Step-by-step explanation:

We can use the vertical angle theorem to solve for most of this problem. We know that 1/3 will have the same measure and so will 4/2. We can create an equation to solve for 1 and 3.

10x = 100

x = 10

We aren't given angle 4 so we are going to have to solve that ourselves. We can create an equation knowing that 4 and 3 will create a supplementary angle.

100 + z = 180

z = 80

Now, that we have angle 4, we know that angle 2 will have the same measure because they are vertical angles. Now to find the value of y, we can take the angle measure and solve for it.

10y + 20 = 80

10y = 60

y = 6

Best of Luck!

3 0
3 years ago
What is the formula for area of a rectangle?
Vedmedyk [2.9K]

Answer:

length × width=Area

I hope this helps

3 0
3 years ago
How do you graph y=-3x-3
netineya [11]

Answer:you go to negative (0,-3) on the y axis then u go down by 3 and then over by 1 and keep doing that to form ur line

Step-by-step explanation:

5 0
3 years ago
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If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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