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Art [367]
2 years ago
6

Find the value of x and y <1=(10x) <2=(10y+20)<3 =100 ​

Mathematics
1 answer:
Rufina [12.5K]2 years ago
3 0

Answer:

  1. 100
  2. 80
  3. 100
  4. 80

x = 10

y = 6

Step-by-step explanation:

We can use the vertical angle theorem to solve for most of this problem. We know that 1/3 will have the same measure and so will 4/2. We can create an equation to solve for 1 and 3.

10x = 100

x = 10

We aren't given angle 4 so we are going to have to solve that ourselves. We can create an equation knowing that 4 and 3 will create a supplementary angle.

100 + z = 180

z = 80

Now, that we have angle 4, we know that angle 2 will have the same measure because they are vertical angles. Now to find the value of y, we can take the angle measure and solve for it.

10y + 20 = 80

10y = 60

y = 6

Best of Luck!

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For a normal distribution, is it likely that a data value selected at random is more than 2 standard deviations above the mean?
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And the best way to solve this problem is using the normal standard distribution and the z score given by:

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And using the complement rule we got:

P(Z>2) = 1-P(Z

And that correspond to only 0.023*100= 2.3%, so is not frequently and the most appropiate answer for this case would be:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interst of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

We are interested on this probability

P(X>\mu + 2\sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score formula we want this probability:

P(Z>2)

And using the complement rule we got:

P(Z>2) = 1-P(Z

And that correspond to only 0.023*100= 2.3%, so is not frequently and the most appropiate answer for this case would be:

No. This event happens only 2.5% of the time

8 0
3 years ago
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