7b-15=5b-3 solve for b
2 answers:
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Answer:
The domain of the function f(x) is:
The range of the function f(x) is:
Step-by-step explanation:
Given the function
Determining the domain:
We know that the domain of the function is the set of input or arguments for which the function is real and defined.
In other words,
- Domain refers to all the possible sets of input values on the x-axis.
It is clear that the function has undefined points nor domain constraints.
Thus, the domain of the function f(x) is:
Determining the range:
We also know that range is the set of values of the dependent variable for which a function is defined.
In other words,
- Range refers to all the possible sets of output values on the y-axis.
We know that the range of an Absolute function is of the form
so
Thus, the range of the function f(x) is:
Answer:
. hole or removable discontinuity at x=2
Step-by-step explanation:
Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)
So let's start by factoring the first equation:
Now let's find what ac is (it's just c since a=1...)
List factors of -6
.
Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...
So using these two factors we get
Ok now let's factor the second equation:
Multiply a and c
List factors of 12:
.
Factors that add up to -7 and multiply to 12:
Rewrite equation:
Group terms:
Factor out GCF:
Rewrite:
Now let's write out the equation using these factors:
.
Here we can factor out the x-2 and the simplified form is:
So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.