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Sidana [21]
3 years ago
15

How do you solve this equation x^1/4+1=0?

Mathematics
1 answer:
malfutka [58]3 years ago
5 0

First, let's isolate x on one side of the equation. To do this, we can subtract 1 from both sides of the equation:

x^{\frac{1}{4}} = -1


Now, we are going to want to get x to a power of 1, since that is what we are looking for after all. To do this, we can set both sides of the equation to the exponent of 4:

(x^{\frac{1}{4}})^4 = (-1)^4

x = 1


We have found x = 1. However, let's check this answer to make sure that it is not an extraneous solution:

1^{\frac{1}{4}} \stackrel{?}{=} -1

1^{\frac{1}{4}} = 1 \neq -1


When we substitute x = 1 into the original equation, we get 1, which is not -1. Thus x = 1 is an extraneous solution. Since there are no other values that we found, the equation has no solutions.

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Step-by-step explanation:

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