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3 years ago

Solve the problem.

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

6 0

Answer:

$2907.89

General Formulas and Concepts:

Symbols

e (Euler's number) ≈ 2.71828

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra i

Compounded Continuously Formula: $\displaystyle A = Pe^{rt}$

P is principle amount
r is rate
t is time

Step-by-step explanation:

Step 1: Define

Identify variables

P = 930

t = 19

r = 6% = 0.06

Step 2: Find Interest

Substitute in variables [Compounded Continuously Formula]: $\displaystyle A = 930e^{19 \cdot 0.06}$
[Exponents] Multiply: $\displaystyle A = 930e^{1.14}$
Evaluate exponents: $\displaystyle A = 930(3.12677)$
Multiply: $\displaystyle A = 2907.89$

You might be interested in

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$