Question

HELPPP...................

Answer 1

$\frac{2y^{2} -7y-15}{3y^{2} -8y-3} * \frac{9y^{2}-1}{4y^{2} -9} +\frac{y^{2}+3y-10}{2y^{2}-9y+9}=\\ \frac{(y-5)(2y+3)}{(3y+1)(y-3)} * \frac{(3y-1)(3y+1)}{(2y-3)(2y+3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=\\ \frac{(y-5)(2y+3)}{(y-3)} * \frac{(3y-1)}{(2y-3)(2y+3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=\\ \frac{(y-5)}{(y-3)} * \frac{(3y-1)}{(2y-3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=\\ \frac{(y-5)(3y-1)}{(y-3)(2y-3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=$
$\frac{(y-5)(3y-1)}{(y-3)(2y-3)} +\frac{(y-2)(y+5)}{(y-3)(2y-3)}=\\ \frac{(y-5)(3y-1)+(y-2)(y+5)}{(y-3)(2y-3)}$