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3 years ago

HELPPP...................

Mathematics

1 answer:

Zarrin [17]3 years ago

4 0

$\frac{2y^{2} -7y-15}{3y^{2} -8y-3} * \frac{9y^{2}-1}{4y^{2} -9} +\frac{y^{2}+3y-10}{2y^{2}-9y+9}=\\
 \frac{(y-5)(2y+3)}{(3y+1)(y-3)} * \frac{(3y-1)(3y+1)}{(2y-3)(2y+3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=\\
 \frac{(y-5)(2y+3)}{(y-3)} * \frac{(3y-1)}{(2y-3)(2y+3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=\\
 \frac{(y-5)}{(y-3)} * \frac{(3y-1)}{(2y-3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=\\
 \frac{(y-5)(3y-1)}{(y-3)(2y-3)} +\frac{(y-2)(y+5)}{(2y-3)(y-3)}=$
$\frac{(y-5)(3y-1)}{(y-3)(2y-3)} +\frac{(y-2)(y+5)}{(y-3)(2y-3)}=\\
 \frac{(y-5)(3y-1)+(y-2)(y+5)}{(y-3)(2y-3)}$

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Plz do 1 and 2 and ill give a like and postive comment

Rama09 [41]

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3 years ago

Assume that random guesses are made for seven multiple choice questions on an SAT test, so that there are n=7 trials, each with

Vedmedyk [2.9K]

Answer:

P(X < 4) = 0.5

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question, we have that:

$n = 7, p = 0.5$

Find the probability that the number of correct answers is fewer than 4:

This is

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{7,0}.(0.5)^{0}.(0.5)^{7} = 0.0078$

$P(X = 1) = C_{7,1}.(0.5)^{1}.(0.5)^{6} = 0.0547$

$P(X = 2) = C_{7,2}.(0.5)^{2}.(0.5)^{5} = 0.1641$

$P(X = 3) = C_{7,3}.(0.5)^{3}.(0.5)^{4} = 0.2734$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0078 + 0.0547 + 0.1641 + 0.2734 = 0.5$

P(X < 4) = 0.5

6 0

3 years ago

Help me out please.

Lostsunrise [7]

Answer:

Step-by-step explanation:

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3 years ago

(06.04 MC) Dennis drew the line of best fit on the scatter plot shown below: What is the approximate equation of this line of be

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

In order to write the equation of this line, we need to pick 2 points on the graph where the line goes right through the intersection of the grids. Actually, you only need 1 of these, because the line goes through at (0, 15). Another point then can be (6, 6). Locate this point so you know what I means when I say that the line goes right through where the grids intersect at x = 6 and y = 6 (as opposed to somewhere in the middle of one of these grids). Find the slope between these 2 points:

$m=\frac{6-15}{6-0}=-\frac{9}{6}=-\frac{3}{2}$

Since there's only one choice with that slope, that is the choice you want.

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3 years ago

Pls help it's due tonight!!! :((((((

statuscvo [17]

I think AB is 3!!

i hope i’m right good luck ,:D

4 0

3 years ago

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