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Maru [420]
3 years ago
6

For the problem below Define a variable write an equation and solve it use the 5D process if needed to help you set up your equa

tion.
for the school play the advance tickets cost $3 while tickets at the door cost $5 30 more tickets were sold at the door than in advance and $2,630 was collected how many of each kind of tickets were sold
Mathematics
1 answer:
Mariulka [41]3 years ago
5 0
D=# of tickets sold at the door
a=# of tickets sold in advance

3a+5d=2630
d=a+30

3a+5(a+30)=2630
8a+150=2630
8a=2480
a=310
d=340

310 tickets were sold in advance and 340 tickets were sold at the door.
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17 13/18 divided by 2 7/9
erik [133]

let's firstly convert the mixed fractions to improper fractions and then divide.

\bf \stackrel{mixed}{17\frac{13}{18}}\implies \cfrac{17\cdot 18 +13}{18}\implies \stackrel{improper}{\cfrac{319}{18}}~\hfill \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{319}{18}\div \cfrac{25}{9}\implies \cfrac{319}{\underset{2}{~~\begin{matrix} 18 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{1}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{25}\implies \cfrac{319}{50}\implies 6\frac{19}{50}

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3 years ago
1. What is the value of x in the figure?<br> (4x + 2)<br> 150°
vlabodo [156]
X = 37
150= 4x + 2
148 = 4x
X = 37
3 0
3 years ago
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
Pam kept track of the puppies available for adoption at the shelter. After 4 hours, there were 7 puppies available for adoption.
Varvara68 [4.7K]
A. 3 hours is the answer
3 0
3 years ago
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Why is there two brainlys? There is Brainly.com then Brainly.in. Is one just a knockoff of the original one?
melomori [17]

Answer:

i think its a <em>knockoff</em>

Step-by-step explanation:

3 0
3 years ago
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