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Maru [420]
4 years ago
6

For the problem below Define a variable write an equation and solve it use the 5D process if needed to help you set up your equa

tion.
for the school play the advance tickets cost $3 while tickets at the door cost $5 30 more tickets were sold at the door than in advance and $2,630 was collected how many of each kind of tickets were sold
Mathematics
1 answer:
Mariulka [41]4 years ago
5 0
D=# of tickets sold at the door
a=# of tickets sold in advance

3a+5d=2630
d=a+30

3a+5(a+30)=2630
8a+150=2630
8a=2480
a=310
d=340

310 tickets were sold in advance and 340 tickets were sold at the door.
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3 years ago
Simple Algebra Equation help.
Ivan

Answer:

There are 3 adult tickets and 7 child tickets

Step-by-step explanation:

You are very close.

Let x = the number of adult tickets

Let y = number of child tickets

24.95x+ 15.95y = 186.50

The total number of tickets is 10

x+y =10

Subtract y from each side

x+y-y = 10-y

x =10-y

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Distribute

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Combine like terms

249.5 - 9y = 186.50

Subtract 249.5 from each side

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Divide each side by -9

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Now we need to find x

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