Question

Josephine's school can be represented by Point A (9,9). Point A can be translated 6 units LEFT and 5 units DOWN to create A', the location of Josephine's house. Which of the following can be used to find the 'd', the diagonal distance between
Point A and Point A' on the grid? Please show your work and answer correctly.
F. 6 squared + 5 squared = d squared
G. 9 squared + 4 squared = d squared
H. d squared + 5 squared = 6 squared
J. 6 squared - 5 squared = d squared

Answer 1

Answer:

F. the distance is $\sqrt{61}$

Step-by-step explanation:

so this is a right triangle.

that means if the diagonal is missing, you can find it by doing $a^{2} +b^{2} = c^{2}$

The "rays" of a triangle are the sides that you know which is 5 and 6. luckily they meet at a right angle. therefore you can plug them in for a and b.

$6^{2} + 5^{2} = d^{2}$

6^2 equals 36

5^2 equals 25

36 + 25 is 61

now just add a square-root sign.

$\sqrt{6} + \sqrt{5} = \sqrt{61}$