J because the x value is used more then once.
Answer:
m = {-6, -4}
Step-by-step explanation:
<u><em>Subproblem 1:</em></u>
Set the factor '(6 + m)' equal to zero and attempt to solve:
Simplifying
6 + m = 0
Solving
6 + m = 0
Move all terms containing m to the left, all other terms to the right.
Add '-6' to each side of the equation.
6 + -6 + m = 0 + -6
Combine like terms: 6 + -6 = 0
0 + m = 0 + -6
m = 0 + -6
Combine like terms: 0 + -6 = -6
m = -6
Simplifying
m = -6
<u><em>Subproblem 2:</em></u>
Set the factor '(4 + m)' equal to zero and attempt to solve:
Simplifying
4 + m = 0
Solving
4 + m = 0
Move all terms containing m to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + m = 0 + -4
Combine like terms: 4 + -4 = 0
0 + m = 0 + -4
m = 0 + -4
Combine like terms: 0 + -4 = -4
m = -4
Simplifying
m = -4
Answer: Because 4 is the base of what is being exponentially multiplied, you can multiply 256 by 4 to get 4^5
Answer:
a(n) = 20*2.5^(n - 1)
Step-by-step explanation:
Note that 50 is 2.5 times 20, and that 125 is 2.5 times 50. Thus the common factor is 2.5. The formula for the nth term is
a(n) = a(1)*r^(n - 1) => a(n) = 20*2.5^(n - 1)
Yes, you are correct.
The two numbers you add to make twenty and have a difference of four are 12 and 8.
