Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
<h3>What is the hang time equation?</h3>
The hang-time of the ball for a player of jump h is given by:
The expression can be simplified as:
For a player that has a hang time of 0.9s, the jump is found as follows:
h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:
h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
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You should be able to set up a proportion between the sides something like (18+x)/x=(56+21)/56
The answer is 0.00010224...
Most of the information's required for finding the answer is already given in the question.
Height of the fly = 12 feet
Width of the fly = 16 feet
Now we can find the length of the poles using Pythagoras theorem.
Length of the poles = square root [(12)^2 + (8)^2]
= square root (144 + 64)
= square root (208)
= 14.4 feet
From the above deduction, we can conclude that the height of the poles needed to be 14.4 feet. I hope the answer has helped you.
Distance formula: distance = sqrt((x2-x1)^2 + (y2 -y1)^2))
Distance = sqrt(( -3 - -3)^2 + (9-4)^2))
Distance = sqrt(25)
Distance = 5
Answer: 5
