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charle [14.2K]
3 years ago
12

PLEASE HELP!!!! A weight is attached to a spring that is oscillating up and down. It takes 3 sec. for the spring to complete one

cycle, and the distance from the highest to lowest point is 4 in. What equation models the position of the weight at time t seconds?
A. y=2sin(pi/3 t)

B. y=4sin(pi/3 t)

C. y=2sin(2pi/3 t)

D. y=4sin(2pi/3 t)

E. y=2sin(3pit)

F. y=4sin(3pit)
Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

Option C.

Step-by-step explanation:

The equation that models the position of the weight and time will be a sine wave.

y = A sin(bt)

where A = amplitude of the wave

b = time period for a complete oscillation

Since b = \frac{2\pi }{t}

It has been given in the question, Time period t = 3 sec.

b = \frac{2\pi }{3}

Amplitude A = 2 in.

Now we plug in the values of amplitude and time period in the standard equation.

y = 2sin(\frac{2\pi }{3}\times t)

y = 2sin(\frac{2\pi t}{3})

Option C. is the answer.

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8 < 8.2 <8.5

Step-by-step explanation:

Pick a number that is greater than 8 but less than 8.5.

Ex: 8.1, 8.2, 8.3, 8.4

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Find the value (18 9) / 3d for d=3
Alexeev081 [22]
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Parentheses
Exponents
Multiplication-Division (in order from right to left)
Addition-Subtraction (in order from right to left)
1. Parentheses- (18*9)=162
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Step-by-step explanation:

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3 years ago
The measures of the angles of a triangle are (3x – 100)°, (x – 10)°, and (x – 10)°.
statuscvo [17]

Answer:

x = 60

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the sum of all three angles in a triangle = 180°

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Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

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\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

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\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

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