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Gala2k [10]
3 years ago
15

Answer the last 2 pls

Mathematics
1 answer:
Genrish500 [490]3 years ago
6 0
C)
2n + 3
first term = 3
second term = 5 (2 + 3 = 5)
third term = 7 ( 4 + 3 = 7)

d)
term 15 that has value greater than 30
cause
2(14) + 3 = 28 + 3 = 31 greater than 30


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The slope of a line that is parallel to each line whose equation is given
Kobotan [32]
Parallel lines, slope is the same so
1) 3x+8y = 12
8y = -3x + 12
  y = -3/8(x) + 3/2, slope = -3/8

slope of a line that is parallel = -3/8

2)5x+4y = 5
  4y = -5x + 5
    y = -5/4(x) + 5/4; slope is -5/4

slope of a line that is parallel = -5/4
--------------------
perpendicular, slope is opposite and reciprocal

3)
3x+8y = 11
 8y = -3x + 11
   y = -3/8(x) + 11/8. slope = -3/8
slope of perpendicular line = 8/3

4)
x = -7, slope is undefined
so slope of perpendicular line is 0

5)
3x+2y = 12
2y = -3x + 12
 y = -3/2(x) + 6 ; slope = -3/2

5x - 6y = 8
6y = 4x - 8
  y = 2/3(x) - 4/3; slope is 2/3

slope is opposite and reciprocal, so the equals are perpendicular

6)
3x + y = 5
y = -3x + 5; slope = -3

6x + 2y = -15
2y = -6x - 15 
y = -3x - 7.5; slope = -3

both have slope = -3 so equations are parallel

3 0
3 years ago
the probability density for a particle in a box is an oscillatory function even for very large energies. Explain how the classic
77julia77 [94]

Answer:

This is achieved for the specific case when high quantum number with low resolution is present.

Step-by-step explanation:

In Quantum Mechanics, the probability density defines the region in which the  likelihood of finding the particle is most.

Now for the particle in the box, the probability density is also dependent on resolution as well so for large quantum number with small resolution, the oscillations will be densely packed and thus indicating in the formation of a constant probability density throughout similar to that of classical approach.

8 0
3 years ago
One number is 1/2 of another the sum of the number is 72 find the numbers
Anton [14]
The answer for the question is 36 , 36
5 0
3 years ago
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
What is the volume, in cubic inches, of a cone that has a radius of 8 inches and a height of 12 inches? Use 3.14 for π , and rou
Doss [256]

Answer:

803.84 in^3

Step-by-step explanation:

First of all we have to find the base area

base area = radius^2 x 3.14 = 8^2 x 3.14 = 64 x 3.14 = 200,96 in^2

the volume can be find with this formula:

V = (base area x height)/3

V = (200.96 x 12)/3 = 803.84 in^3

8 0
3 years ago
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