All categories

3 years ago

Help needed I need the answer with work shown for the graphs

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

6 0

top left: speed = 2.7 miles per hour = 2.7 MPH

top right: speed = 0 miles per hour = 0 MPH

bottom left: speed = 4 miles per hour = 4 mi/h

bottom right: speed = 2 miles per hour = 2 mi/h

and so, the fastest is bottom left. And pay attention in class! i'm in highschool and Iearned this in 6th grade!

Step-by-step explanation:

key: speed= distance/time

distance= speedxtime

time=distance/speed

top left: 8/3= 2.66667 MPH= 2.7 MPH

top right: 0/8= 0 MPH= 0 MPH

bottom left: 8/2= 4 MPH= 4 MPH

bottom right: 8/4= 2 MPH= 2 MPH

You might be interested in

Rosa ran the hurdles in 58.32 seconds. maya ran the hurdles in 54.078 seconds. what is the difference between the two times? 3.9

satela [25.4K]

Answer:

Step-by-step explanation: 4.242

5 0

1 year ago

2^3 x 2^6 x 2^? = 2^12

kow [346]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Rename the value of $780,000

ANEK [815]

Seven hundred and and eighty thousand

6 0

3 years ago

50% of what number is 140?

babunello [35]

Answer:

The answer is 70

3 0

3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is

$F_{critical} = 1.8608$

Generally the test statistics is mathematically represented as

$F = \frac{s_1^2 }{s_2^2}$

=> $F = \frac{8324 }{2862}$

=> $F = 2.9085$

Generally from the value obtained we see that $F > F_{critical }$ Hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to support the researchers claim

4 0

2 years ago