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sleet_krkn [62]
3 years ago
13

1,495 divided by 45 please help me before tomorrow

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0
299/9 is the correct answer
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Solve for x only type in numbers what are these called​
Brilliant_brown [7]

Answer:

25

Step-by-step explanation:

3 0
3 years ago
The total mass of the Sun is about 2×10^30 kg, of which about 76 % was hydrogen when the Sun formed. However, only about 12 % of
nignag [31]

Answer:

A. 1.8 ×10^{30} Kg

B i. 3.0 × 10^{17} seconds

  ii. 9.6 × 10^{9} years

C. After 9.2 × 10^{9} (9.2 billion) years

Step-by-step explanation:

Given that the mass of the Sun = 2× 10^{30} Kg.

Mass of hydrogen when Sun was formed = 76% of 2× 10^{30} Kg

                            = \frac{76}{100}  ×2× 10^{30} Kg

                           = 1.52 × 10^{30} Kg

Mass of hydrogen available for fusion = 12% of 1.52 × 10^{30} Kg

                           = \frac{12}{100} × 1.52 × 10^{30} Kg

                           = 1.824 ×10^{30} Kg

A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 ×10^{30} Kg.

B. Given that the Sun fuses 6 × 10^{11} Kg of hydrogen each second.

i. The Sun's initial hydrogen would last;

                                     \frac{1.8*10^{30} }{6*10^{11} }

                                 = 3.04 × 10^{17} seconds

The Sun's hydrogen would last 3.0 × 10^{17} seconds

ii. Since there are 31536000 seconds in a year, then;

The Sun's initial hydrogen would last;

                                     \frac{3.04*10^{17} }{31536000}

                                 = 9.640 × 10^{9} years

The Sun's hydrogen would last 9.6 × 10^{9} years.

C. Given that our solar system is now about 4.6 × 10^{9} years, then;

                               \frac{9.6*10^{9} }{4.6*10^{9} }

                             = 2.09

So that;   2 × 4.6 × 10^{9} = 9.2 × 10^{9} years

Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × 10^{9} years.

6 0
3 years ago
Find the nth term of this sequence 1 5 9 13 17
nata0808 [166]
A = 1, d = 5 - 1 = 4
nth term = a + (n - 1)d = 1 + (n - 1)4 = 1 + 4n - 4 = 4n - 3
nth term = 4n - 3
4 0
3 years ago
Read 2 more answers
The expression above can also be written in the form a=, b=,c=. 3 6/5
brilliants [131]

Answer:

a = 3, b = 6, c = 5

Step-by-step explanation:

{3}^{ \frac{6}{5} }  =  \sqrt[5]{ {3}^{6} }  \\ equating \: it \: with \\  \sqrt[c]{ {a}^{b} }  \: we \: find :  \\ a = 3 \:  \: b = 6 \:  \: c = 5 \\

7 0
3 years ago
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Help please look at the image <br> Thanks
IgorC [24]

Answer: Option 1

Reason: Math

3 0
3 years ago
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