Question

A, B and C share a bag of sweets between each other in the proportions 4:8:2. If A received 452 sweets Ba) How many did B get? FTotalb) How many sweets were there in total?

Answer 1

Answer:  a) B would get 904 sweets.

b) There are 1582 sweets in total.

Step-by-step explanation:

Since we have given that

Ratio of share of bag of sweets in A, B, and C is given by 4:8:2.

Number of sweets A received = 452

Since part of sweets A would get = $\dfrac{4}{14}=\dfrac{2}{7}$

So, it becomes

$\dfrac{2}{7}x=452\\\\x=\dfrac{452\times 7}{2}\\\\x=1582$

so, B would get

$\dfrac{8}{14}\times 1582\\\\=904$

Hence, a) B would get 904 sweets.

b) There are 1582 sweets in total.