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KiRa [710]
3 years ago
15

(WORTH 20 POINTS)

Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0
So the function is
f(x)=3( \frac{1}{3})^{ x }
the intial value is where x=0
where x=0, the value of f(0)=3

grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9


the true things are

The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .



Hitman42 [59]3 years ago
6 0

The initial value of the function is 2.

The base of the function is 3.

The function shows exponential growth.

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Step-by-step explanation:

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Answer:  (-\infty, -4]

Curved parenthesis at negative infinity

Square bracket at -4

====================================================

Work Shown:

5(x+4) \le 0 \\\\x+4 \le \frac{0}{5} \\\\x+4 \le 0 \\\\x \le 0-4 \\\\x \le -4 \\\\

The last inequality shown above is the same as saying -\infty < x \le -4

Converting this to interval notation leads to the final answer of (-\infty , -4]

Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.

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