(WORTH 20 POINTS)
2 answers:
So the function is
the intial value is where x=0
where x=0, the value of f(0)=3
grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9
the true things are
The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .
the intial value is where x=0
where x=0, the value of f(0)=3
grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9
the true things are
The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .
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9514 1404 393
Answer:
16.4
Step-by-step explanation:
The law of cosines is useful here. It tells you ...
b^2 = a^2 + c^2 -2ac·cos(B)
b^2 = 22^2 +10^2 -2·22·10·cos(44°)
b^2 ≈ 267.49
b ≈ √267.49 ≈ 16.35514
b ≈ 16.4
