Question

(WORTH 20 POINTS)

Answer 1

So the function is
$f(x)=3( \frac{1}{3})^{ x }$
the intial value is where x=0
where x=0, the value of f(0)=3

grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9


the true things are

The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .

Answer 2

The initial value of the function is 2.

The base of the function is 3.

The function shows exponential growth.