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3 years ago

Solve the system of equations. y =9x y =2x + 63

Mathematics

2 answers:

Zielflug [23.3K]3 years ago

8 0

<span>y=2x+7
y=9x+8
From (1),
x= (y-7)/2
Substituting value of x in eqn (2) we get,
y= 9.(y-7)/2 + 8</span>

Olin [163]3 years ago

7 0

Y=9x and
y=2x+63

subsitute 9x for y

9x=2x+63
minus 2x from both sides
9x-2x=2x-2x+63
7x+0=63
7x=63
divide both sides by 7
7x/7=63/7
(7/7)x=9
(1)x=9
x=9

sub back to find y

y=9x
y=9(9)
y=81

(x,y)
(9,81)

the solution is (9,81)

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What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.

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The value of x in the equation $(x-5)^{2} +3(x-5)+9=0$ is x=(7+3 $\sqrt{3}i$ )/2,

(7-3 $\sqrt{3}i$ )/2.

Given equation $(x-5)^{2} +3(x-5)+9=0$ .

We have to find the solution of the equation.

Equation is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes $u^{2} +3u+9=0$

solution of a quadratic formula

x=-b± $\sqrt{b^{2} -4ac}$ /2a

on comparing with general form a=1,b=3, c=9

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=-3± $3\sqrt{3} i/2$

$u_{1} =-3$ +3 $\sqrt{3}/2$ , $u_{2}$ =-3-3 $\sqrt{3}/2$

put the values of $u_{1}$ in equation 1

x-5= $u_{1}$

x-5=-3+ $3\sqrt{3} /2$

x=-3+3 $\sqrt{3}i/2+5$

x=7+3 $\sqrt{3} i/2$

put the values of $u_{2}$ in equation2

x-5= $u_{2}$

x-5=-3-3 $\sqrt{3} /2$

x=7-3 $\sqrt{3}/2$

Hence the values of x are 7+3 $\sqrt{3}i/2$ , 7-3 $\sqrt{3}i/2$ .

Learn more about equation at brainly.com/question/2972832

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