Answer:
<em>He bought 6 hotdogs and 2 drinks</em>
Step-by-step explanation:
<u>System of Equations</u>
Kevin and his children went into a restaurant and bought $31.50 worth of hotdogs and drinks. Each hotdog costs $4.50 and each drink costs $2.25.
To solve the system of equations, we'll call the variables:
x = number of hotdogs
y = number of drinks
The first condition yields the equation:
4.50x + 2.25y = 31.50 [1]
It's also known he bought 3 times as many hotdogs as drinks, thus:
x = 3y [2}
Substituting [2] in [1]:
4.50(3y) + 2.25y = 31.50
Operating:
13.5y + 2.25y = 31.50
15.75y = 31.50
y = 31.50/15.75
y = 2
And
x = 3*2 = 6
He bought 6 hotdogs and 2 drinks
Answer:
A 234.11
Step-by-step explanation:
is what you get lol
Answer:
1) b and m
2) m∠8=m∠6
3) 160°
4)x=60°
Step-by-step explanation:
1) all straight lines sum to 180°
subtract the angles given from 180°
the other angle for b is 25°, while the other angle for m is 155°
so we can see that the angles for both lines are the same, hence they are parallel.
2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4
in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.
3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°
(2x-16)°+(7x+20)°=180°
we get x=20(nearest whole number)
∠CED=7x+20=7(20)+20=160°
4) since we need to show that they are parallel,
(2x+30)°=(4x-90)°
2x-4x=-90-30
-2x=-120
x=60
we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)
I hope u understand it the way I put it.
Answer:
C
Step-by-step explanation:
When you find the volume for the cone and cylinder they are both 235.62
Answer:
7/5 y --> y+ 2/5y
0.68y --> y - 0.32y
3/5y --> y - 2/5y
1.32y --> y+ 0.32y
Step-by-step explanation:
Pretend there is a 1 in front of each y that doesn't have a number (coefficient) in front of it. 1 = 5/5, and then just solve for the fraction expressions.
