The distance of plane from the origin is 357.14 miles
<u>Explanation:</u>
Given:
distance traveled southwards, y = 600 miles
Distance traveled east of south, z = 250 miles
Angle, θ = 35°
Distance of plane from the origin, x = ?
The figure is attached for reference:
tan θ = Perpendicular / base
tan θ = distance travelled east of south / x
tan 35° = 250 / x
we know,
tan 35° = 0.7
So,
Therefore, the distance of the plane from the origin is 357.14 miles
Answer:
The answer is 9x2+33x+30 :)
Step-by-step explanation:
(3x+5)(3x+6)
=(3x+5)(3x+6)
=(3x)(3x)+(3x)(6)+(5)(3x)+(5)(6)
=9x2+18x+15x+30
=9x2+33x+30
I agree with the given answer because of the gain or loss on retirement of bonds = book value of bonds - the amount paid to the bondholders
Answer:
<em>8.1</em><em> </em><em>ft</em>
Step-by-step explanation:
hyp² = side² + side²
hyp² = 7² + 4²
hyp² = 49 + 16
hyp² = 65
hyp = sqrt of 65
hyp = 8.1 ft
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