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elena-s [515]
3 years ago
7

Can somone give me the answer to 2 x 0

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0
Any number times 0 is going to equal 0
Rzqust [24]3 years ago
6 0
Ur answer is 0...!!!!
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SOLVE FOR X<br><br> -5x + 9 = 24
boyakko [2]

Answer:

<u>x = -3</u>

Step-by-step explanation:

-5x + 9 = 24

move the nine to the other side

-5x = 15

divide

x = -3

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Answer:

C. 63.4

Step-by-step explanation:

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Which expression is equivalent to (3x squared -7) The answer is (10x squared -4) - (7x squared +3)
WITCHER [35]

Answer:

(10x squared -4) - (7x squared +3)

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Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the
BigorU [14]

The average travel time is simply the mean travel time between the given points

  • The average time that it takes for the car to travel the first 0.25m is 2.23s.
  • The average time to travel just between 0.25m and 0.50m is 0.9s.
  • Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

Time = \frac{2.24s + 2.21s + 2.23s}{3}

Time = \frac{6.68s}{3}

Time = 2.23s

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

Time = \frac{3.16s + 3.08s + 3.15s}{3}

Time = \frac{9.39s}{3}

Time = 3.13s

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

Average = 3.13s - 2.23s

Average = 0.9s

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

Distance = 0.25m

Time = 0.9s

So, the velocity is:

Velocity = \frac{Distance}{Time}

This gives

Velocity = \frac{0.25m}{0.9s}

Velocity = 0.28m/s

Read more about distance, velocity and time at:

brainly.com/question/4931057

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