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kari74 [83]
4 years ago
12

Simplify to create an equivalent expression:7(5+2c)+3c

Mathematics
2 answers:
Harrizon [31]4 years ago
6 0
Use distributive property on the first half of the equation:

35+14c+3c

Then just add the like terms

35+17c
Arte-miy333 [17]4 years ago
3 0
7x7c+3c that’s all I know hope it helps
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If A = {2,4,6,8,}, write the set A by description method​
belka [17]

Step-by-step explanation:

Set-builder notation is a notation for describing a set by indicating the properties that its members must satisfy.

C={2,4,6,8}

C={2×1,2×2,2×3,2×4}

thus set builder form is:

{x:x=2n,n∈N} and this set is also call even number set in description mathod

6 0
3 years ago
Simplify expressions
charle [14.2K]
<h3>a) \frac{2}{5}  \div (  - \frac{3}{4} )</h3><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2>-  \frac{2}{5}  \div  \frac{3}{4}</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2>

<h3>Hence, Quotient =-  \frac{8}{15}</h3>

<h3>b) 0.4 \div  ( - 0.75)</h3><h3>■Convert the decimals into a fractions</h3>

<h2>\frac{2}{5}  \div ( -  \frac{3}{4} )</h2><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2>-  \frac{2}{5}  \div  \frac{3}{4}</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2><h3>Hence, Quotient is -  \frac{8}{15}</h3>

<h3>c)-  \frac{2}{5}  \div  \frac{3}{4}</h3><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2><h3>Hence, The Quotient is -  \frac{8}{15}</h3>
4 0
3 years ago
True-False: Please select true or false and click "submit."
harina [27]
A true


because 53•(41•11)=23,903 and (53•41)•11=23,903


Hope this helped
4 0
3 years ago
Read 2 more answers
Integrate 1 - x / x(x2 + 1) d x by partial fractions.
solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

step 1:-   by using partial fractions

[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }......(1)

<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 }  d x -\int\limits \frac{1}{x^{2}+1 }  d x

by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

\int\limits tan^{-1}x  dx =\frac{1}{1+x^{2} } +C.....(c)

<u>step 4:-</u>

by using above integration formulas (a,b,and c)

we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

6 0
3 years ago
Find the interest due on $600 at 9.5% for 120 days.
KATRIN_1 [288]

Answer:

Interest= $ 18.73

Step-by-step explanation:

Given : $600 at 9.5% for 120 days

To find : Find the interest due

Solution :

Simple interest formula  I=P\times r\times t

Principle(P)=$600 , rate(r)=9.5%=0.095 , time (t)= 120 days

In years, 1 year = 365 days

1 day = \frac{1}{365} year

120 days = \frac{120}{365} year

Put values in the formula

I=P\times r\times t

I=600\times 0.095\times\frac{120}{365}

 I=\frac{6840}{365}=18.73

Therefore, Interest= $ 18.73




5 0
3 years ago
Read 2 more answers
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