= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
49w² -112w + 64
first, you have to find 2 numbers that add up to equal -112, but also multiply together to get a product of 3136 (49 * 64)
two numbers that add to -112 and multiply to equal 3136 is -56 and -56
we can add them into the equation by putting them in for -112x
49w²-56w-56w+64
we now look at what the first 2 numbers have in common and what the last two numbers have in common
49w² and -56w both have w and 7 in common so we can divide 7w
7w(7w -8)
-56w and 64 both have -8 in common so we can divide by -8
-8(7w-8)
now we take the 2 numbers on the outside and bring down the numbers in the brackets
(7w-8)(7w-8)
(7w-8)²
Answer:
see below
Step-by-step explanation:
For a vertical scale factor of 'b', and a translation by (h, k) in the (right, up) direction, the transformed function is ...
g(x) = b·f(x -h) +k
For a scale factor of 1/2 and translation left 3 and down 2, the transformed function is ...
g(x) = (1/2)f(x +3) -2
g(x) = (1/2)5^(x +3) =2 . . . . matches the 2nd choice
Answer:
x=1
Step-by-step explanation:
_3× +1=2(4×_5)
_3×+1=8×_10
-3×_8×=_10-1
11×=_11
=1
Given :
Insurance cost , $693.00 .
Gas cost , $452.00 .
Average charge per fare , $7.00 .
Tuition fee , $3280.00 .
To Find :
The fare he have to get to pay his fee .
Solution :
Let , number of fair required is n .
Therefore , total profit is :
Now , to pay his fee this profit must be equal to his fee because he don't have other expenditure .
So ,
But number of rides cannot be in decimal so minimum rides he must get is
632+1 = 633 .
Hence, this is the required solution .
