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Blizzard [7]
3 years ago
5

Please help me with number 7

Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

"twelve decreased by twice a number"   --->   12 - 2x

"8 times the sum of number and 4"   --->   8(x + 4)

12 - 2x  =  8(x + 4)

12 - 2x  =  8x + 32                    (distributive property)

12        =  10x + 32                   (add 2x to both sides)

-20       =  10x                           (subtract 32 from both sides)

x  =  -2                                      (divide both sides by 10)

That's answer.
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Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
Can someone please help me??
Mars2501 [29]

Answer:

3x^{3} +10x^{2} +17x+12

Step-by-step explanation:

5 0
3 years ago
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PLZ HELP WILL GIVE BRAINS :)
kipiarov [429]
It would be 75 cents per song, I hope you get a good grade!
5 0
3 years ago
Find the unpaid balance on the debt after 5 years of monthly payments on $190,000 at 3% for 25 years
NNADVOKAT [17]

Answer:

$114,000

Step-by-step explanation:

Use formula

I=P\cdot r\cdot t,

where

I = interst

P = principal

r = rate

t = time

First, find the interst for 25 years:

I = unknown

P = $190,000

r = 0.03 (3% as decimal)

t = 25

I_{25}=190,000\cdot 0.03\cdot 25=142,500

Now find the interest for 5 years:

I = unknown

P = $190,000

r = 0.03 (3% as decimal)

t = 5

I_5=190,000\cdot 0.03\cdot 5=28,500

The unpaid balance is

I=I_{25}-I_5=142,500-28,500=114,000

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3 years ago
What is the interval notation for the compound inequality? x is less than or equal to -4 or x is greater than or equal to 5?
Tems11 [23]

x is less than or equal to -4 or x is greater than or equal to 5

x <= -4 or x>= 5

There is no intersection of both inequalities when we graph it in number line So, we write the interval notation separately for each inequality

for x<=-4 , x starts at -4  and goes to -infinity because we have less than symbol. Also we have = sign so we use square brackets

Interval notation is (-∞ , -4]

for x>= 5 , x starts at 5  and goes to infinity because we have greater than symbol. Also we have = sign so we use square bracket at 5

Interval notation is [5 , ∞)

Now combine both notation by a 'U' symbol Union

(-∞ , -4] U [5 , ∞)

5 0
3 years ago
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