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3 years ago

15

Simplify 5+4x(8-6)^2

2 answers:

NARA [144]3 years ago

8 0

Ok Use PEMDAS Since 8 and 6 is in pharenthesis you do that first which equals 5+4x2^2 Then you do Exponents which is 2^2 that equals 4 so that means you have 5+4x4 No you multiply 4x4 which equals 16 And now add 5 That will make 21

Vikki [24]3 years ago

3 0

Help me first and then ill help you

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During a sale, a store offered a 20% discount on a TV that originally sold for $710. After the sale, the discounted price of the

Mademuasel [1]

Answer:

$681.60

Step-by-step explanation:

<u><em>Given:</em></u>

<em>During a sale, a store offered a 20% discount on a TV that originally sold for $710. After the sale, the discounted price of the TV was marked up by 20%</em>

<u><em>To Find:</em></u>

<em>What was the price of the TV after the markup? Round to the nearest cent.</em>

<u><em>Solution:</em></u>

$710 × (1 + 20%) × (1 - 20%)

$710 × 1.2 × (1-0.2)

$710 × 1.2 × 0.8

($710 × 1.2) × 0.8

852 × 0.8

= $681.60

<u><em>Kavinsky</em></u>

4 0

2 years ago

Can someone please help me with this!?!?!

lys-0071 [83]

They are congruent because of the angles, which means the congruency reason should be SAS.

4 0

3 years ago

What is the perimeter of Justin's garden in inches? I can't find the right answer 6 yards and 8 yards its a rectangle garden pls

madreJ [45]

Answer:

28 yards

Step-by-step explanation:

It's perimeter so you add (6x2)+(8x2)

The x2 is because there's 2 of each side

3 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

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3 years ago

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likoan [24]

Answer:

3 tee shirts and 2 dresshirts

Step-by-step explanation:

3 0

3 years ago