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Brilliant_brown [7]
3 years ago
8

As Alejandro prepares for his basketball game, he has several choices to make. He can pick from three pairs of socks (green, whi

te or black), two pairs of sneakers (high-tops or low-tops), and eight different wristbands (all different colors). How many different ways can Alejandro dress for the game if he chooses one item from each category? A. 13 ways B. 8 ways C. 48 ways D. 56 ways
Mathematics
1 answer:
Veronika [31]3 years ago
3 0

Answer:

C. 48 ways

Step-by-step explanation:

3 x 2 x 8 = 48 ways

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Marti’s photo album has a total of 45 pictures. Each page holds 4 pictures. She said she can only fill 10 pages completely.
amm1812

Answer:

She can only fill 10 pages completely.

Step-by-step explanation:

She can fill 10 pages, because 40/10=4.  She does not have enough pages left to fill another page fully.

8 0
3 years ago
Find the area of the parallelogram that has a base of 23 cm and a height of 17 cm.
astraxan [27]

The area of the parallelogram is 391 cm².

The area of a parallelogram is calculated by multiplying the base by the height.

A=b×h

A=23 cm×17 cm

A=391 cm²

8 0
3 years ago
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F(x) = (x - 6)^2(x + 2)^2<br> How many roots ?
baherus [9]

Answer:

Two double roots in this case.

I could say 4, but you have a pair of double roots  x = 6 and x = -2

Step-by-step explanation:

x = 6 is a double root of f(x)

x = -2 is a double root of f(x)

7 0
3 years ago
The plane of a room is shown in the picture. the scale is 2 inches: 6 feet. what is the actual length of the room?
valentina_108 [34]

Since 2 inches = 6 ft and length of room in the place = 7 inches,

(2x3.5) inches = 6x3.5 ft

7 inches = 21ft

Actual Length of Room = 21 ft.

Width of Room in plane = 3 inches

(2x1.5) inches = 6 x 1.5 ft

= 9 ft

Actual Length of Rook = 9 ft.

Actual Area of Room = Actual Length of Room x Actual Width of Room = 21 x 9 = 189 ft^2

8 0
3 years ago
Can y = sin(t2) be a solution on an interval containing t = 0 of an equation y + p(t) y + q(t) y = 0 with continuous coefficient
JulsSmile [24]

Answer:

Step-by-step explanation:

y = sin(t^2)

y' = 2tcos(t^2)

y'' = 2cos(t^2) - 4t^2sin(t^2)

so the equation become

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when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.

7 0
3 years ago
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