681/4 i dont know this
2 answers:
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>7</em><em>0</em><em>.</em><em>2</em><em>5</em>
<em>pl</em><em>ease</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> </em><em>solution</em>
<em>hope </em><em>it</em><em> helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
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9514 1404 393
Answer:
- 7.5 ft
- 32.5 ft, 5 ft
- 10.7 ft
Step-by-step explanation:
a) The starting height is h(0) = 7.5 feet, the constant in the quadratic function.
The irrigation system is positioned <u> 7.5 </u> feet above the ground
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b) The axis of symmetry for quadratic ax^2 +bx +c is x = -b/(2a). For this quadratic, that is x=-10/(2(-1)) = 5. This is the horizontal distance to the point of maximum height. The maximum height is ...
h(5) = (-5 +10)(5) +7.5 = 32.5 . . . feet
The spray reaches a maximum height of <u> 32.5 </u> feet at a horizontal distance of <u> 5 </u> feet from the sprinkler head.
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c) The maximum distance will be √32.5 + 5 ≈ 10.7 ft.
The spray reaches the ground at about <u> 10.7 </u> feet away.
