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Nikolay [14]
3 years ago
6

A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Two marbles are drawn from the bag.

Mathematics
2 answers:
kherson [118]3 years ago
6 0

Answer:

It is the third option: (10C1) (20C1( / 50C2.

Step-by-step explanation:

The number of ways of selecting 2 marbles = the number of combination of any 2 marbles in the 50 marbles in the bag and this is 50C2. It is combinations because the order of drawing the marbles does not matter.

The number of combinations  of one being red and the other blue =  10C1 times 20C1.

So the answer is (10C1) (20C1( / 50C2.

AfilCa [17]3 years ago
3 0

Answer:

its C

Step-by-step explanation:

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astraxan [27]

Answer:

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Step-by-step explanation:

Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.

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YZ=7 units, XZ=11 units and YM=3.5 units

By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.

Hence, \frac{YM}{MX}=\frac{YZ}{XZ}

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