A rectangular photograph is mounted on a poster and has a two inch border on each side. The poster itself is mounted on a frame
whose sides are the same length as the sides of the poster. The frame cost $2 per inch and the cost of the frame was $160. If the area of the photograph is 231 inches squared. What are the dimensions of the frame?
Let's define variables: w: width of the photograph l: length of the photograph The cost of the box is: 2 * (2 * (w + 2)) + 2 * (2 * (l + 2)) = 160 The area is: (w + 2) * (l + 2) = 231 Solving the system of equations we have: w = 5 inches l = 31 inches Then, the dimensions of the frame are: w + 2 = 7 inches l + 2 = 33 inches Answer: the dimensions of the frame are: 7 inches * 33 inches
The area is found by multiplying length times width. So, since you already have one of the sides of the room, you just divide the area by by that side. 132.9 ÷ 10.9 = 12.2
