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Veronika [31]
4 years ago
10

A rectangular photograph is mounted on a poster and has a two inch border on each side. The poster itself is mounted on a frame

whose sides are the same length as the sides of the poster. The frame cost $2 per inch and the cost of the frame was $160. If the area of the photograph is 231 inches squared. What are the dimensions of the frame?
Mathematics
1 answer:
kap26 [50]4 years ago
6 0
Let's define variables:
 w: width of the photograph
 l: length of the photograph
 The cost of the box is:
 2 * (2 * (w + 2)) + 2 * (2 * (l + 2)) = 160
 The area is:
 (w + 2) * (l + 2) = 231
 Solving the system of equations we have:
 w = 5 inches
 l = 31 inches
 Then, the dimensions of the frame are:
 w + 2 = 7 inches
 l + 2 = 33 inches
 Answer:
 
the dimensions of the frame are:
 
7 inches * 33 inches
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Answer:

The amount they charged to wash a car is <u>$6</u> and vacuum a car is <u>$2</u>.

Step-by-step explanation:

Given:

Trisha and Byron are washing and vacuuming cars to raise money for a class trip.

Trisha raised $38 washington 5 cars and vacuuming 4 cars.

Byron raises $28 by washing 4 cars and vacuuming 2 cars.

Now, to find the amount they charged to wash a car and vacuum a car.

Let the amount charged for washing a car be x.

And the amount charged for vacuuming a car be y.

So, the total amount Trisha raised:

5x+4y=38........(1)

And, the total amount Byron raised:

4x+2y=28.

Now, to get the amount they charged to wash a car and vacuum a car we use elimination method:

5x+4y=38\\4x+2y=28......\times 2

5x+4y=38\\8x+4y=56

-3x=-18

3x=18

<em>Dividing both sides by 3 we get:</em>

x=6.

<u>Amount charged to wash a car = $6.</u>

Now, putting the value of x in equation (1) we get:

5(6)+4y=38.

5\times 6+4y=38

30+4y=38.

<em>Subtracting both sides by 30 we get:</em>

4y=8.

<em>Dividing both sides by 4 we get:</em>

y=2.

<u>Amount charged to vacuum a car = $2.</u>

Therefore, the amount they charged to wash a car is $6 and vacuum a car is $2.

5 0
3 years ago
Somebody help me on this
amm1812
38/7.

This is because you can multiply the terms after the log and set them equal to 10^1. or simply 10. This would give you 7(x-4)= 10. Solve for x. 
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