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Veronika [31]
3 years ago
10

A rectangular photograph is mounted on a poster and has a two inch border on each side. The poster itself is mounted on a frame

whose sides are the same length as the sides of the poster. The frame cost $2 per inch and the cost of the frame was $160. If the area of the photograph is 231 inches squared. What are the dimensions of the frame?
Mathematics
1 answer:
kap26 [50]3 years ago
6 0
Let's define variables:
 w: width of the photograph
 l: length of the photograph
 The cost of the box is:
 2 * (2 * (w + 2)) + 2 * (2 * (l + 2)) = 160
 The area is:
 (w + 2) * (l + 2) = 231
 Solving the system of equations we have:
 w = 5 inches
 l = 31 inches
 Then, the dimensions of the frame are:
 w + 2 = 7 inches
 l + 2 = 33 inches
 Answer:
 
the dimensions of the frame are:
 
7 inches * 33 inches
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The value of (f-g)(144) is 0

Step-by-step explanation:

We are given:

f(x)=\sqrt{x}+12\,\,and\,\,\\ g(x)=2\sqrt{x}

We need to find value of (f-g)(144)

We will put x=144 for both f(x) and g(x)

(f-g)(144)=f(144)-g(144)\\=\sqrt{144}+12-(2\sqrt{12})\\=12+12-(2(12)\\=24-24\\=0

So, the value of (f-g)(144) is 0

Keywords: Composite Functions

Learn more about Composite Functions at:

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4 years ago
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3 years ago
Bryan owes his friend more than $1,930 from a loan. Bryan has already paid his friend back $200 and continues to pay him $173 ea
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Answer:

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