Answer:
ok
Step-by-step explanation:
The domain- Is the function provides an "output" or value for each member of the domain
Range- The difference between the lowest and highest values.
}
Answer:B
Step-by-step explanation: I said that because you have 27 and 50 Cent so basically you won't have that $5 in that picture because you still going to have that $0.04 and then you still have to have that much so I I think I am right but if I'm not I'm so sorry but I'm taking not even to get I'm trying to get back on track but I think is b for a reason like I think you could be because you have 27 and 50 Cent so if you got twenty-seven fifty cents you just rounding it down
<h2>
Hello!</h2>
The answer is:
The correct option is the third option,
![L(p(x))=2.425(1.082)^{x}](https://tex.z-dn.net/?f=L%28p%28x%29%29%3D2.425%281.082%29%5E%7Bx%7D)
<h2>
Why?</h2>
From the statement we know the function that models the population growth over the years (p(x)) but we have been told that there is an estimated loss that can be modeled by the function L(p), so in order to find which function represents the final function, we need to composite the function, which is the same that evaluate p(x) into the function L(p).
We are given:
![p(x)=2.5(1.082)^{x}](https://tex.z-dn.net/?f=p%28x%29%3D2.5%281.082%29%5E%7Bx%7D)
and
![L(p(x))=p(0.97)](https://tex.z-dn.net/?f=L%28p%28x%29%29%3Dp%280.97%29)
So, the evaluationg p(x) into L(p), we have:
![L(p(x))=p(0.97)\\\\L(p(x))=2.5(1.082)^{x}*(0.97)=0.97*2.5(1.082)^{x} \\\\L(p(x))=0.97*2.5(1.082)^{x}=2.425(1.082)^{x}\\\\L(p(x))=2.425(1.082)^{x}](https://tex.z-dn.net/?f=L%28p%28x%29%29%3Dp%280.97%29%5C%5C%5C%5CL%28p%28x%29%29%3D2.5%281.082%29%5E%7Bx%7D%2A%280.97%29%3D0.97%2A2.5%281.082%29%5E%7Bx%7D%20%5C%5C%5C%5CL%28p%28x%29%29%3D0.97%2A2.5%281.082%29%5E%7Bx%7D%3D2.425%281.082%29%5E%7Bx%7D%5C%5C%5C%5CL%28p%28x%29%29%3D2.425%281.082%29%5E%7Bx%7D)
Hence, the correct option is:
The third option,
![L(p(x))=2.425(1.082)^{x}](https://tex.z-dn.net/?f=L%28p%28x%29%29%3D2.425%281.082%29%5E%7Bx%7D)
Have a nice day!