Please help with atleast one question ❤️

Mathematics

1 answer:

Stolb23 [73]3 years ago

6 0

Answer:

not quite sure about these, too hard to read

Step-by-step explanation:

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Evaluate the expression when c=4,d=6 and e=10

natima [27]

Errrmmm.... Where is the expression?

6 0

3 years ago

Here's a more clear picture for you guys sorry the last one was fuzzy.

sergeinik [125]

RhTh + RsTs = 180 (Rh = 70, Rs=20 , Th = Ts)
70Th + 20Th = 180
90 Th = 180
Th = 2
since Th = Ts,
thus, Ts = 2

6 0

3 years ago

Consider the line x+5y=6

Tems11 [23]

Answer:

$x + 5y = 6$ is perpendicular to $y = 5x + \frac{6}{5}$ and parallel to $y = -\frac{1}{5}x + 2\\$

Step-by-step explanation:

First, convert the equation to standard form so that y is isolated.

x + 5y = 6 --> x - 6 = -5y (divide both sides by -5) --> $y = -\frac{1}{5}x + \frac{6}{5}$

A perpendicular line will have a slope that is the opposite reciprocal of the original slope (meaning you flip the numerator and denominator then make it negative).

$-\frac{1}{5}$ is perpendicular to $-(\frac{-5}{1} )$ which simplifies to 5.

A parallel line will have the same slope, but the y-intercept will be different. It can be pretty much any number as long as the original slope is used in the new equation.

$y = -\frac{1}{5}x + \frac{6}{5}\\$ is parallel to $y = -\frac{1}{5}x + 2\\$ just like $y = -\frac{1}{5}x - \frac{100}{23}$ .