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kakasveta [241]
3 years ago
6

The ratio 125:x is equivalent to the ratio x squared:125. What is the value of x?

Mathematics
1 answer:
Serhud [2]3 years ago
3 0

You said that                            125/x = x²/125

Cross-multiply the proportion:      x³  =  (125)²

                                                            = 15,625

                                             So    x  =  ∛15,625  =  25 .
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15 = -3(2c + d) (Solve for c)​
Paha777 [63]

Answer:

(15+3d)/6 = c

2 1/2 + 1/2d = c     (more simplified)

Step-by-step explanation:

15 = -3(2c +d)

15 = -6c -3d

+3d       +3d

15 +3d = -6c

/-6          /-6

(15+3d)/6 = c

2 1/2 + 1/2d = c

7 0
3 years ago
Red and grey bricks were used to build a decorative wall. The number of red bricks and grey bricks was 5/2. There were 140 brick
ozzi

Answer:

100 red bricks

Step-by-step explanation:

Let's say red bricks is equal to 5x

Gray bricks is equal to 2x

We have an equation

2x + 5x = 140

= 7x = 140

Divide through by 7 to get the value of x

X = 140/7

X = 20

Red bricks = 5(x)

= 5(20)

= 100

Gray bricks = 2(x)

= 2(20)

= 40

Therefore in conclusion the number of red bricks is 100.

5 0
2 years ago
The histogram below shows information about the number of hamburgers students ate in a month:
Travka [436]
The given histogram represents <span>the number of hamburgers students ate in a month :
</span>
From the histogram we can conclude the following:
(1) 8 students ate (0 - 4) hamburgers 
(2) 3 students ate (5 - 9) <span>hamburgers </span>
(3) 2 students ate (10 - 14) <span>hamburgers
</span>
note: we don't know how many students ate exactly 5 hamburgers.

<span>So, the answer
</span>
The information which is provided in the histogram<span>
</span><span>
</span><span>The number of students who ate 10 hamburgers or more </span>



7 0
3 years ago
Read 2 more answers
How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation
mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

5 0
3 years ago
What is the slant height ?
LekaFEV [45]

Answer:

32 or 34 I multiply 18 by 4 to get it

6 0
3 years ago
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