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KIM [24]
3 years ago
14

Find the original price of a salt lamp that is $76 after a 20% discount.

Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0

Answer:

$76 x 1.20 = $92

$92 / 1.20 = $76

To keep and show decimals we divide 20 by 100 to show 1.02 then show any 2 placement decimals if none are shown in draft first then you can try in draft 20/1000 to see the difference between the decimals.

Step-by-step explanation:

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Eight is less than twice its number
Anni [7]

Answer:

2x-8

Step-by-step explanation:

From the question the meaning of the expression is

Let the number be x

2x - 8

I hope this was helpful, please mark as brainliest

3 0
3 years ago
Which ordered pair is a solution of the equation?
True [87]

Answer:

Step-by-step explanation: try your best

8 0
2 years ago
Read 2 more answers
If y varies inversely as x and } = 3 when x = 4, then y
Andrews [41]

Answer:

FALSE

Step-by-step explanation:

If y varies inversely as x., this is expressed as;

y = k/x

k is the proportionality constant

when y = 3 and x = 4

3 = k/4

k = 3 * 4

k = 12

when x = 15;

y = k/x

y =12/15

y = 4/5

Hence y is not equal to 12 when x = 15.

The correct answer is FALSE

5 0
2 years ago
Solve:<br> 3x - 9 = 5(x-3)
Viefleur [7K]

Hi,

3x - 9 = 5(x-3)\\3x - 9 - 5(x-3)= 0\\3x -9 -5x +15 =0\\6-2x=0\\6=2x\\x=3

Have a good day.

3 0
3 years ago
Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang
PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence  f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence  f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx  = 2x

since  d(fx))/dx  = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0
2 years ago
Read 2 more answers
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