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Nookie1986 [14]
3 years ago
12

1. Calculate Q3 of the following data:

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

4.75

Step-by-step explanation:

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How would you write "there were 3 times as many baby dinosaurs as adult dinosaurs" as an algebraic equation where x = baby dinos
Mrrafil [7]
X = 3y

hope it helped!
5 0
2 years ago
Read 2 more answers
14 - 8 + 3 + 8 × [24 ÷ 8}
Kryger [21]

Step-by-step explanation:

14 - 8 + 3 + 8 × [24 ÷ 8}

14 - 8 + 3 + 8 × [3}

14-8+3+24= 33

= 33

3 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL GIVE BRAINLY.
igomit [66]

Answer:

<u>330,000</u>

Explanation:

Since the two numbers given have the same degree, <u>move the decimal point to the right by the amount of the degree</u> (in this case, move the decimal point to the right 6 times). Now, you have <u>560,000</u> and <u>230,000</u>. Now subtract 230,000 from 560,000, and you get <u>330,000</u> as your answer

3 0
3 years ago
Kayla's making ribbons for school spirit day a roll of ribbon is 32 ft long for each individual ribbon she needs .64 ft how many
svp [43]

Kayla can make 50 ribbons for the show using 32 feet ribbon

<u>Solution:</u>

Given, Kayla's making ribbons for school spirit day a roll of ribbon is 32 ft long  And for each individual ribbon she needs 0.64 ft  

We have to find how many ribbons can she make for her old show.

Number of ribbons that can be made is found out by dividing total available ribbon by ribbon length required for single ribbon

\text { number of ribbons can be made }=\frac{\text { total available ribbon length. }}{\text { ribbon length required for single ribbon }}

\begin{array}{l}{=\frac{\text { total } 32 \text { feet }}{0.64 \text { for each ribbon }}} \\\\ {=\frac{32}{0.64}} \\\\ {=50 \text { ribbons }}\end{array}

Hence, Kayla can make 50 ribbons for the show using 32 feet ribbon.

8 0
4 years ago
Find the mean of 5<br> 10<br> 15<br> 20<br> 2<br> 2
Artemon [7]

Answer:

9

Step-by-step explanation:

To calculate the mean, you add up all the values and divide by the number of values:

M = (5 + 10 + 15 + 20 + 2 + 2) \div 6\\M = 9

5 0
3 years ago
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